7p^2=7p+6

Solution for 7p^2=7p+6 equation:

7p^2=7p+6

We move all terms to the left:

7p^2-(7p+6)=0

We get rid of parentheses

7p^2-7p-6=0

a = 7; b = -7; c = -6;
Δ = b2-4ac
Δ = -72-4·7·(-6)
Δ = 217
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{217}}{2*7}=\frac{7-\sqrt{217}}{14}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{217}}{2*7}=\frac{7+\sqrt{217}}{14}
$